30 C++ Jump To Case Label
You cannot declare variables inside case statements. If the value isnt in the jump table it will jump to the default location.
By jumping backwards to a point before the declarations of such variables or by jumping forward out of a compound.
C++ jump to case label. The following example raises c2362. So i would not say that allowing one to jump to default. Otherwise statement labels are ignored.
Labels cannot be redeclared. In cc switch statements allows fall through semantics with the case labels. You declared a findword variable when your switch statement encounters case f or f.
That is what the assembly does. Unfortunately in c it doesnt compile. Jump to case label.
Case statements are only labelsthis means the compiler will interpret this as a jump directly to the label. A statement label is meaningful only to a goto statement. This results in them being in the scope of every case statement.
To solve this make findword in its own scope or declare it outside the switch statements. In c the problem here is one of scope. If transfer of control exits the scope of any automatic variables eg.
As ciro santilli 包子露宪 六四事件 法轮功 explained we simply cant jump to case 2 because this would skip the declaration with initialization of i and even though case 2 doesnt use i at all this is still forbidden in c. It would actually make as much sense to have default as just another label that is the default if non match. A goto statement is not allowed to transfer control to a location that skips over the initialization of any variable that is in scope in that location.
Your curly brackets define the scope as everything inside the switch statement. C c forums on bytes. This means that you are left with a scope where a jump will be performed further into the code skipping the initialization.
To limit the scope of the newly declared variable enclose the case statements in brackets to limit the scope to the current case statement. The goto statement transfers control to the location specified by labelthe goto statement must be in the same function as the label it is referring it may appear before or after the label. Post your question and get tips solutions from a community of 444258 it pros developers.
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